I=12.6r^2

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Solution for I=12.6r^2 equation: 



=12.6I^2

We move all terms to the left:

-(12.6I^2)=0

We get rid of parentheses

-12.6I^2=0

a = -12.6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12.6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$I=\frac{-b}{2a}=\frac{0}{-25.2}=0$

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